[Solved] Spiral Matrix in JavaScript

  

3
Topic starter

Write a JS function that generates a Spirally-filled matrix with numbers, with given dimensions.

The input comes as 2 numbers that represent the dimension of the matrix.

The output is the matrix filled spirally starting from 1. You need to print every row on a new line, with the cells separated by a space. Check the examples below.

Examples:

Input:

5, 5

Output:

1 2 3 4 5

16 17 18 19 6

15 24 25 20 7

14 23 22 21 8

13 12 11 10 9


Input:

3.3

Output:

1 2 3

8 9 4

7 6 5

1 Answer
2

The code js:

function generateSpiralMatrix(row, col) {
    let rows = row;
    let cols = col;
 
    let matrix = [];
    for (let row = 0; row < rows; row++) {
        matrix[row] = [];
        for (let col = 0; col < cols; col++) {
            matrix[row][col] = 0;
        }
    }
 
    let top = 0;
    let bottom = rows - 1;
    let left = 0;
    let right = cols - 1;
 
    let index = 1;
    let direction = 0;
    while (top <= bottom && left <= right) {
        switch (direction % 4) {
            case 0:
                for (let col = left; col <= right; col++) {
                    matrix[top][col] = index++;
                }
                top++;
                direction++;
                break;
            case 1:
                for (let row = top; row <= bottom; row++) {
                    matrix[row][right] = index++;
                }
                right--;
                direction++;
                break;
            case 2:
                for (let col = right; col >= left; col--) {
                    matrix[bottom][col] = index++;
                }
                bottom--;
                direction++;
                break;
            default:
                for (let row = bottom; row >= top; row--) {
                    matrix[row][left] = index++;
                }
                left++;
                direction++;
                break;
        }
    }
 
    console.log(matrix.map(r => r.join(' ')).join('\n'));
}
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