3
06/11/2024 11:05 am
Topic starter
Write a JavaScript function that finds the elements at even positions in an array. The input comes as array of string elements.
Examples:
Input:
['20', '30', '40']
Output:
20 40
Input:
['5', '10']
Output:
5
The output is the return value of your function. Collect all elements in a string, separated by space.
1 Answer
2
06/11/2024 11:07 am
Here are my JS solutions:
function evenPosition(arrayString) {
let result = [];//creating new array named result - to put there the elements from the even positions there
for (let i in arrayString) {
if (i % 2 == 0) {
result.push(arrayString[i]);
}
}
console.log(result.join(" "));
}
evenPosition(['20', '30', '40']);
function evenCheck(arr) {
let arrFiltered = [];
arrFiltered = arr.filter((x, i)=>i % 2 == 0);//functional programming
console.log(arrFiltered.join(" "));
}
evenCheck(['5', '10', '30', '77']);
The code in 1 row - thanks to the functional programming:
(arrayEven) => arrayEven.filter((x, i)=>i % 2 == 0).join(" ");
